Two radiactive material `A_(1)` and `A_(2)` have decay constants of `10 lambda_(0)` and `lambda_(0)`. If initially they have same number of nyclei, the ratio of number of their undecayed nuclei will be `(1//e)` after a time

Two radioactive material A_(1) and A_(2) have decay constants of 10 lambda_(0) and lambda_(0) . If initially they have same number of nuclei, then after time (1)/(9 lambda_(0)) the ratio of number of their undecayed nuclei will be

Two radioactive materials X_(1) and X_(2) have decay constant 11 lambda and lambda respectively. If initially they have same number of nuclei, then ratio of number of nuclei of X_(1) to X_(2) will be (1)/(e^(2)) after a time

Two radioactive materials X_(1) and X_(2) have decay constant 11 lambda and lambda respectively. If initially they have same number of nuclei, then ratio of number of nuclei of X_(1) to X_(2) will be (1)/(e^(2)) after a time

Two radioactive materials X_(1) and X_(2) have decay constant 11 lambda and lambda respectively. If initially they have same number of nuclei, then ratio of number of nuclei of X_(1) to X_(2) will be (1)/(e) after a time

Two radioactive materials A and B have decay constants 10lambda and lambda , respectively. If initially they have the same number of nuclei, then the ratio of the number of nuclei of A of that of B will be 1//e after a time :

Two radioactive material A and B have disintegration constants 10lambda and2lambda respectively. If initially they have same number of nuclei, then the ration of number of nuclei of A and B will be (1)/(e) after a time of :

Two radioactive material A and B have decay constants 10 lambda and lambda , respectively. If initially they have a the same number of nuclei, then the ratio of the number of nuclei of A to that of B will be 1//e after a time 1/(n lambda) , where n is ___________

Two radioactive materials X_(1) and X_(2) have decay constants 10 lambda and lambda respectively. If initially they have the same numbers of nucle, then the ratio fo the nclie of X_(1) to that X_(2) will be 1//e after a time: