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HCN is a weak acid (Ka=6.2xx10^(-10)).NH...

HCN is a weak acid `(K_a=6.2xx10^(-10)).NH_4` OH is a weak base `(K_b=1.8xx10^(-5)).` A 1 M solution of `NH_4CN` would be

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NH_(4)CN is a salt of weak acid HCN(K_(a)=6.2xx10^(-10)) and a weak base NH_(4)OH(K_(b)=1.8xx10^(-5)) . 1 molar solution of NH_(4)CN will be :-

NH_(4)CN is a salt of weak acid HCN(K_(a)=6.2xx10^(-10)) and a weak base NH_(4)OH(K_(b)=1.8xx10^(-5)) . 1 molar solution of NH_(4)CN will be :-

NH_(4)CN is a salt of weak acid HCN (Ka=6.2xx10^(-10)) and a weak base NH_(4)OH(K^(b)=1.8xx10^(-5)) A one molar solution of NH_(4)CN will be :-

NH_4F is a salt of weak acid HF ( ka = 7.2 xx 10^(-4)) and weak base NH_4OH ( kb = 1.8 xx 10^(-5)) , the solution of NH4F will be

For 10^(-4) M BOH (weak base) , K_(b)=5xx10^(-5)) :

For 10^(-4) M BOH (weak base) , K_(b)=5xx10^(-5)) :

For NH_(3) , K_(b)=1.8xx10^(-5) . K_(a) for NH_(4)^(+) would be

For NH_(3) , K_(b)=1.8xx10^(-5) . K_(a) for NH_(4)^(+) would be

A weak acid (K_a = 2 xx 10^(-6) ) and a weak base ( K_b = 5 xx 10^(-7) ) form a salt. Calculate the hydrolysis constant.