Product of means=Product of extremes

If x:15=y:6, then find the value of (x+y)/(x-y) The following problem. Arrange them is sequential order. (A) Applying componendo-dividendo. (B) Product of means=Product of extremes. ltBrgt (C) (x+y)/(x-y)=(7)/(3) (D) (x)/(y)=(5)/(2) (E) 6x=15y

Divide 96 into four parts which are in A.P. and the ratio between product of their means to product of their extremes is 15 : 7.

Divide 32 into four parts which are in A.P. such that the ratio of the product of extremes to the product of means is 7:15.

Divide 32 into four parts which are in A.P. such that the ratio of the product of extremes to the product of means is 7:15.

Divide 32 into four parts which are in A.P.such that the ratio of the product of extremes to the product of means is 7:15.

Divide 32 into four parts which are in A.P. such that the ratio of the product of extremes to the product of means is 7:15.

Divide 32 into four parts which are in A.P. such that the ratio of the product of extremes to the product of means is 7:15.

Divide 32 into four parts which are in A.P.such that the product of extremes is to the product of means is 7:15.

Divide 32 into four parts which are in A.P. Such that the product of extremes is to the product of means is 7: 15