[" If the function "f(x)={[(sqrt(2+cos x)-1)/((pi-x)^(2)),,x!=pi],[k,,x=pi]" is "],[" continuous at "x=pi," then "k" equals: "]

If the function f(x)={((sqrt(2+cosx)-1)/(pi-x)^2 ,; x != pi), (k, ; x = pi):} is continuous at x = 1, then k equals:

If f(x)={((sin(cosx)-cosx)/((pi-2x)^2) ,, x!=pi/2),(k ,, x=pi/2):} is continuous at x=pi/2, then k is equal to

If the function f(x)=(sqrt(5+cos x)-2)/((pi-x)^(2)) is continuous at x=pi, find f(pi)

If the function f(x)=(sqrt(5+cos x)-2)/((pi-x)^(2)) is continuous at x=pi, find f(pi)

Find the value of k, the function, f(x)={:{((1-sinx)/((pi-2x)^(2))", "x!=(pi)/(2)),(" k, "x=(pi)/(2)):} is continuous at x=(pi)/(2) .

f(x)={(sin(cos x)-cos x)/((pi-2x)^(2)),x!=(pi)/(2);k,x=(pi)/(2) is continuous at x=(pi)/(2), then k is equal to 0 (b) (1)/(2)(c)1(d)-1

f(x)={(sin(cos x)-cos x)/((pi-2x)^(3)),quad if x+-(pi)/(2) and k,quad if x=(pi)/(2) is continuous at x=(pi)/(2), then k

f(x)={[2x tan x-(pi)/(cos x),,x!=(pi)/(2)k,x=(pi)/(2)quad is continuous at x=(pi)/(2)