" If the first three terms of "(1)/(16),a,b,(1)/(6)" are in GP and last three terms are in HP then "4a+b=

If first three terms of the sequence 1/16,a,b,(1)/(6) are in geometric series and last three terms are in harmonic series,then find the values of aandb.

If first three terms of the sequence 1/16 ,a , b , 1/6 are in geometric series and last three terms are in harmonic series, then find the values of a , bdot

If first three terms of the sequence 1//16 ,a , b , 1/6 are in geometric series and last three terms are in harmonic series, then find the values of a a n d bdot

If first three terms of the sequence 1//16 ,a , b , c1//16 are in geometric series and last three terms are in harmonic series, then find the values of aa n dbdot

32. The integers 2, a, b, c, 160 are such that the first three terms in A.P. while the last three terms are in GP. Ifthe common ratio ofthe G.P. and common difference of the A.P are equal, then the value of a +b+ c is (A) 56 (B) 64 (C) 72 (D) None of these

The sum of the first three terms of a G.P. is 16 and the sum of the next three terms is 128. (i) Determine the first term and common ratio. (ii) Find also the sum of n terms of the G.P.

The sum of first three terms of a G.P. is (1)/(8) of the sum of the next three terms. Find the common ratio of G.P.

The sum of first three terms of a G.P. is (1)/(8) of the sum of the next three terms. Find the common ratio of G.P.

In a GP, the sum of the first three terms is 32, and the sum of the next three terms is 256. Then find the common ratio and first term of G.P.

In a GP, the sum of the first three terms is 125, and the sum of the next three terms is 3,375. Find the common ratio and first term of GP