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0.004 g of NaOH is present in 1L of a...

`0.004 g ` of NaOH is present in 1L of a solution. The pH of the solution is

A

`14.0`

B

` 12.0`

C

` 10.0`

D

` 8.0 `

Text Solution

Verified by Experts

The correct Answer is:
C

`n= (0.004) /(40 ) = 10 ^(-4) ,V =1L `
` therefore [OH^(-) ] =(10 ^(-4))/( 1) = 10 ^(-4)`
` therefore POH = 4 rArr pH = 14- 4 = 10 `
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