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The [OH]^(-)] of 0.005 M H(2)SO(4) is...

The `[OH]^(-)]` of 0.005 M `H_(2)SO_(4)` is

A

`2xx 10^(-12) M`

B

` 5xx10 ^(-3) M`

C

` 10^(-2) M`

D

` 10^(-12) M`

Text Solution

Verified by Experts

The correct Answer is:
D
` [H^(+) ] =( 5 xx 10 ^(-3) ) 2 , [H^(+) ][OH^(-) ] = 10 ^(-14) `
` 10 ^(-2) =[OH^(-) ] = 10 ^(-14) rArr [OH^(-) ] = 10 ^(-14) rArr [OH^(-) ] 10 ^(-12) M `
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AAKASH SERIES-IONIC EQUILIBRIUM -LECTURE SHEET (EXERCISE -II LEVEL -I (MAIN) (Straight Objective Type Questions))
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  2. The P^(H) of 0.005 M Ba (OH)(2) is

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  6. The p^(H) of 0.1 M NaCI solution is

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  15. A monoprotic acid in a 0.1 M solution ionizes to 0.001 % . Its ionizat...

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  16. The hydrogen ion concentration of 0.2 M CH3 COOH which is 4% ionised ...

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