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K(sp) (BaSO(4)) is 1.1 xx 10^(10). In w...

`K_(sp) (BaSO_(4))` is ` 1.1 xx 10^(10).` In which case is `BaSO_(4)` precipitated ?

A

`100 mL of 4xx 10^(-3) M of BaCl _2 +300 mL of 6.0 xx 10^(-4) M of Na_2SO_4`

B

` 100 mL of 4xx 10^(-4) M of BaCl _2+ 300 mL of 6xx 10^(-8) M of Na_2SO_4`

C

` 300 mL of 4xx 10^(-4) M of BaCl_2 +100 mL of 6.0 xx 10 ^(-8) M of Na_2SO_4`

D

in all cases

Text Solution

Verified by Experts

The correct Answer is:
A
Before mixing ` [Ba^(+2) ]= 4 xx 10 ^(_3) M rArr [SO_4^(-2)] = 6 xx 10 ^(-4) M `
after mixing,
` 4 xx 10 ^(-3) xx 100 =M_2xx 400`
` [ Ba^(+2) ] = 10 ^(-3) M`
` 6 xx 10 ^(-4) xx 300 = M_2 xx 400`
` [SO_4^(-2) ]=4.5 xx 10^(-4) M`
` IP =[Ba^(+2) ][SO_4^(-2) ]= 4.5 xx 10 ^(-7) ,KsP lt I.P.`
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