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The K, of an indicator HIn is 9 x 10^(4)...

The K, of an indicator HIn is `9 x 10^(4)`, The percentage of the basic form of indicator is 10x in a solution of pH = 4. What is x ?

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The correct Answer is:
9

` pH =pK_(In) +log"" (In^(-))/( HI_n) , 4 =4- log 9 +log ""(In^(-))/(HI_n)`
` 9= ( In^(-))/( HI_n) rArr % " of " In^(-) =90 %`
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AAKASH SERIES-IONIC EQUILIBRIUM -LECTURE SHEET (EXERCISE -IV LEVEL -II (ADVANCED) (Integer Type Questions))
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  8. A saturated 0.01 M H(2) S solution is buffered at pH =3 with exactly s...

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  10. Calculate the pH at which an acid indicator with Ka =1.0 xx 10^(-5) ch...

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  11. The K, of an indicator HIn is 9 x 10^(4), The percentage of the basic ...

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  12. K(sp) of M(OH)(x), is 27 xx 10^(-12) and its solubility in water is 10...

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  13. Solubility products of ACO3 , BSO4 and ASO4 are 4xx10^(-10) , 6xx 10^...

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  14. The solubility product of a springly soluble metal hydroxide [M(OH)2] ...

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  15. The solubility product of SrF(2) in water is 8xx10^(-10) Calculate it...

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  16. Few drops of dilute solution of AgNO3 are added to a litre of 0.1 M so...

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  17. A saturated 0.01 M H(2) S solution is buffered at pH =3 with exactly s...

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  18. Calculate the concentration of free silver ion [Ag^(+) ] in an aqueous...

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