`K_(sp)` of `M(OH)_(x)`, is `27 xx 10^(-12)` and its solubility in water is `10^(-3)` mol `litre^(-1)` . Find the value of X

Answer

3

Explanation

` M(OH) _x hArr underset(S) M^(x+) +X underset( xs) OH^(-) `
` K_(sp) =S(XS)^(x) `
` 27 xx 10 ^(-12) = (10 ^(-3)) ( X 10 ^(-3)) ^(x) `
` 27 xx 10 ^(_12) = 10 ^(-3-3x) , X^(x) rArr 3^(3) =27 ,x=3`