Solubility products of `ACO_(3), BSO_(4)`, and `ASO_(4)`, are `4 xx 10^(-10), 6 xx 10^(-10)` and `8 xx 10^(-10)` respectively. The solubility product of `BCO_(3)`, is x x `10^(-10)`, What is x ?

Answer

3

Explanation

` ([A^(+2) ][CO_3^(-2)] )/([A^(+2)][SO_4^(-2)]) =(1)/(2) ,[SO_4^(-2) ] =2 [CO_3^(-2) ]`
` [B^(+2) ][SO_4^(-2) ] = 6 xx 10 ^(-10) `
` [B ^(+2) ] 2 [CO_3^(-2) ]=6 xx 10 ^(_10) `
` [B^(+2) ][CO_3^(-2) ]=3xx 10 ^(-10) `