The solubility product of `SrF_(2)` in water is `8xx10^(-10)` Calculate its solubility in 0.1 M of aqueous NaF solution. If its solubility is expressed as `y xx 10^(-8)` then what is the value of 'y' ?

Answer

8

Explanation

` SrF_2hArr underset(S) Sr^(+2) +underset( 2S) (2F) ^(-) `
` [F^(-) ] " from " 0.1 M NaF " is " 0.1 M`
Total ` [F^(-) ] =0.1 +2S = (0.1 )^(2) `
` K_(sp) = S( 0.1) ^(2) rArr(8xx 10 ^(-10) )/( 10^(_2)) =SrArr S = 8 xx 10 ^(-8) `