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The dissolution of ammonia gas in water ...

The dissolution of ammonia gas in water does not obey Henry's law. On dissolving. a major portion of ammonia molecules unite with `H_(2),O` to form `NH_(4),OH` molecules. A portion of the latter again dissociates into `NH_(4)^(+)`, and `OH^(-)` ions. In solution thercfore, we have `NH_(3)`, molecules, `NH_(4),OH` molecules and `NH_(4)^(+)`, ions and the following equilibrium exist:
`NH_(3(g))` (pressure P and concentration c) `rarr NH_(3(l)) + H_(2),Orarr NH_(4),OH rarr NH_(4)^(+) rarr,+OH^(-)`
Let `c_(1)`,mol/L of `NH_(3)`, pass in liquid state which on dissolution in water forms `c_(2)` mol/ L of `NH_(4),OH.` The solution contains `c_(3)`mol/L of `NH_(4)^(+)`, ions.
Total concentration of ammonia, which can be determined by volumetric analysis is equal to:

A

`c_1 `

B

` c_1+c_2+c_3`

C

` c_1+c_3`

D

` c_2+c_3`

Text Solution

Verified by Experts

The correct Answer is:
A
` [NH_3] =(C_1 -C_1 alpha_1 ) + C_2(1- alpha _2) + C_3(C_1-C_2) +(C_2-C_3) +C_3=C_1`
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