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100 ml of 0.1 M NaCl and 100 ml of 0.2 M...

100 ml of 0.1 M NaCl and 100 ml of 0.2 MNaOH are mixed. What is the change in pH of NaCI solution ?

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The correct Answer is:
6

pH of 100 ml of 0.1 M NaCl = 7
` [OH^(-) ] (100xx 0 + 100 xx 0.2 )/( 200) =(20)/( 200) =(1)/( 20 ) = 0.1`
`pOH =1 , pH =13`
change in pH of NaCl =` 13 - 7= 6`
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