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If 50 ml of 0.2M KOH is added to 40 ml ...

If 50 ml of 0.2M KOH is added to 40 ml of 0.5 M `HCOOH.` the pH of the resulting solutions is `(Ka = 1.8 xx 10^(-4) log 18= 1.26) `

A

` 3.74`

B

` 5.64`

C

` 7. 57 `

D

` 3.42`

Text Solution

Verified by Experts

The correct Answer is:
A
In complete neutralisation
` therefore " Acidic buffer pH " = pKa +log ""( S)/(A) `
` = 4- log 1.8 + log"" ( 50 xx 0.2 )/( 40 xx 0.5 -50 xx 0.2 ) `
` =4-0.26 +log "" (10)/(20 - 10 ) = 3.74`
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