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H2 O+ H3 PO3 hArr H3O^(+) +H2O PO3^(-) ...

`H_2 O+ H_3 PO_3 hArr H_3O^(+) +H_2O PO_3^(-) ,pK_1 = x`
` H_2O +H_2PO_3 hArr H_3 O^(+) HPO_3 ^(-2) , pK_2 =y`
Hence , pH of 0.01 M `NaH_2 PO_3` is :

A

`x+y`

B

` (x+y)//2`

C

` (x+y)^(1//2)`

D

` (x+y)^(1//3)`

Text Solution

Verified by Experts

The correct Answer is:
B
` NaH_2 PO_3 ` is amphiprotic salt
` pH= ( pK_1 + pK_2)/( 2 ) =(x+y)/(2) `
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