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The pH of 0.05 M aqueous solution of die...

The pH of 0.05 M aqueous solution of diethyl amine is 12.0. The `K_(b) = x xx 10^(-3)` then what is x value?

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The correct Answer is:
2
`pH = 12, pOH =2`
` pOH = (1)/(2) (pK_b -log C) `
` 2= (1)/(2) (pK_b-log ( 5 xx10 ^(_2))) `
`pK_b -log 5 +2=4 rArr pK_b =2+ 0.7=2.7`
` -log K_b =2.7 rArr K_b = 10 ^(-2.7) =10 ^(-3+0.3) `
Anti log ` (0.3 ) xx 10 ^(-3) = 2xx 10 ^(-3) `
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