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A 0.1 M solution of weak acid HA is 1% d...

A 0.1 M solution of weak acid HA is 1% dissociated at `25^(@)`C To this solution NaA is added till [NaA] = 0.2 M, if the new degree of dissociation of HA =` yxx 10^(-5)` then what is 'y'?

Text Solution

Verified by Experts

The correct Answer is:
5
` alpha = 0.01 , C =0.1`
` K_a = Calpha ^(2) = 0.1 xx ( 0.01 )^(2) = 10 ^(5) `
` K_a = ([H^(+) ] [A^(-) ]) /( [HA]) =([H^(+) ]xx 0.2 )/( 0.1 ) `
` rArr [H^(+) ] = calpha =10 ^(-5) xx ( 0.1)/( 0.2 ) rArr alpha = 5 xx 10 ^(-5)`
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