The molar solubility in mol. `lit^(-1)` of a sparingly soluble salt `MX_(4)`, is S. The corresponding solubility product `K_(sp)`, is given by the relation

Options

A. `S= (K_(sp)//128 ) ^(1//4)`
B. ` S= (218 K_(sp))^(1//4)`
C. ` S= (256 K_(sp) )^(1//5)`
D. ` S= (K_(sp) //256 )^(1//5) `

Answer

D

Explanation

` MX_4 hArr underset(S) M^(4+) + 4underset( 4S) X^(-) `
` K_(sp) =[M^(4+ ) ][X^(-)] ^(4) = S( 4S)^(4) =256 S^(5) `
` S = (K_(sp ) // 256) ^(1//5) `