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The solubility of AgCl in 0.1M NaCI is (...

The solubility of AgCl in 0.1M NaCI is `(K_(sp) " of AgCl" = 1.2 xx 10^(-10)) `

A

`0.1 M `

B

` 1.2 xx 10 ^(-5) `

C

` 1.095 xx 10 ^(-5)`

D

` 1.2 xx 10 ^(-9) `

Text Solution

Verified by Experts

The correct Answer is:
D
`AgCl hArr Ag^(+) +Cl^(-) `
` " " s " " 0.1`
`Ksp= 5 xx 0.1 rArr S =1.2 xx 10 ^(-9) `
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AAKASH SERIES-IONIC EQUILIBRIUM -PRACTICE SHEET (EXERCISE -IV LEVEL -I (MAIN) (Straight Objective Type Questions))
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