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Let the colour of the indicator (Hin col...

Let the colour of the indicator (Hin colourles) will be visible only when its ionised form (pink) is 25 or more in a solution. Suppose Hln `(pK_(In) = 9.0)` is added to a solution of pH = 9.6. Predict what will happen. (Take log 2 = 0.3)

A

Pink colour will be visible

B

Pink colour will not be visible

C

% of ionised form will be less than 25%

D

% of ionised form will be more than 25%

Text Solution

Verified by Experts

The correct Answer is:
A, D
` pH =pKa +log "" ([In^(-) ])/( [HIn]) , `
` 9. 6 = 9+ log ""([In^(-) ])/( [HIn ]) , 0. 6 = log ""([ In^(-)])/( [HIn ]) , ([In^(-) ])/( [H In ]) = 4 `
` rArr ([In^(-) ])/( [In ^(-) ]+ [HIn ]) xx 100 = (4)/(3) xx 100 = 80 %`
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