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pH of aqueous solution of 0.1 M , NH4 C...

pH of aqueous solution of 0.1 M , `NH_4 Cl` is found to be 5. The equilibrium constant for the neutralization of `NH_4 OH ` by HCl is `10 ^(y) `. The value of .y. is

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The correct Answer is:
9
` [H^(+) ]= sqrt(CKa) =10 ^(-5) ,K_a =(10^(-10))/( 10^(-1)) =10 ^(-9)`
` K_ n =(1)/(K_n) =(K_b)/(K_w) =(1)/(K_a) =(1)/(10^(-9) ) =10 ^(9) `
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