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Calculate the solubility of CaF(2) in wa...

Calculate the solubility of `CaF_(2)` in water at 298 K which is 70% dissociated. `K_(sp)` of `CaF_(2)` is `1.7 xx 10^(-10)`. If answer is x `xx 10^(-4)` mol/ltr then x = ____?

Text Solution

Verified by Experts

The correct Answer is:
5
`CaF_2 hArr underset( 0.75) (Ca^(+2) ) +underset( 1.4s) (2F^(-))`
` 1.7 xx 10^(-10) =(0.7S) (1.4S) ^(2) `
` 1.7xx 10^(-10) =1.4 xx S^(3) rArr S= 5 xx 10 ^(_4) `
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