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What is the percent composition of a mix...

What is the percent composition of a mixture of `(S)-(+)-2-` butanol, `[+-](25)/(D)=+13.52^(0)`, and `(R)-(-)-2-` butanol, `[+-](25)/(D)=-13.52^(0)`, with a specific rotation `[+-](25)/(D)=+6.76^(0)`?

A

75%(R) 25%(S)

B

25%(R) 75%(S)

C

50%(R) 50%(S)

D

67%(R) 33%(S)

Text Solution

Verified by Experts

The correct Answer is:
A
`75%(R)25%(S)`
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