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Total number of stereoisomers of the fol...

Total number of stereoisomers of the following compound is `CHCl=CH-CH(CH_(3))C_(2)H_(5)`

A

2

B

4

C

6

D

8

Text Solution

Verified by Experts

The correct Answer is:
B
`CHCl=CH-underset(CH_(3))underset(|)CH-C_(2)H_(5)` The compound has one double bond and one chiral centre. It forms two geometrical (cis & Trans) and two optical isomers. Hence the total number of isomers are four.
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Write IUPAC names of the following compounds : (CH_(3))_(2)C(C_(2)H_(5))_(2)

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Knowledge Check

  • The number of diastereomeric pairs and enantiomeric pairs respectively in the set of stereo isomers of the compound CHCl=CH-CH(CH_(3))C_(2)H_(5) are

    A
    2, 2
    B
    1, 1
    C
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    D
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    A
    2
    B
    3
    C
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    D
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  • Number of stereoisomers possible for BrCH_2 CH Cl CH_2 CH Cl CH_3Br

    A
    two
    B
    three
    C
    four
    D
    six

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