An enantiomerically pure acid is treated with racemic mixture of an alcohol having chiral carbon, The ester formed will be

Options

A. mixture of diastereomers
B. mixture of enantiomers
C. meso compound
D. racemic mixture

Answer

A

Explanation

`underset("pure acid")underset("Enantiomerically")overset(R+)darr` `underset("racemic mixture")[{:( R ),(+),(S):}]`
`{:("[R",,"R]"),(,"+",),("[R",,"S]"):}}` Misture of Diastereomers
Enantiomerically pure acid (R (or) S) is treated with racemic mixture `[50%R + 50%S]` of an alconol it gives mixture of diastereomers