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Find out number of heavy water molecules...

Find out number of heavy water molecules present in one drop of ordinary water whose volume is 0.05ml (density of `H_2O` = 1g/ml).

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Weight of one drop of water = density of water x volume of water drop `=1xx0.05=0.05g`
1g of `D_(2)O` is present per 6000 g of ordinary water.
Weight of `D_(2)O` present in `0.05` g of ordinary water `=(1)/(6000)xx0.05=0.833xx10^(-5)g`
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