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Electrolysis of 50%" "H(2)SO(4) produces...

Electrolysis of `50%" "H_(2)SO_(4)` produces

A

`H_(2)S_(2)O_(8)` at anode

B

`H_(2)SO_(5)` at cathode

C

`H_(2)` at anode

D

`H_(2)O_(2)` at anode & Cathode

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The correct Answer is:
A
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