Calculate the weight of calcium calcium carbonate required to produce carbondioxide that is sufficient for conversion of one decimole sodium carbonate to sodium bicarbonate.

Explanation

Step 1: Regarding the requirement of cabon dioxide:
The balanced equation for conversion of sodium carbonate to sodium bicarbonte is
`Na_(2)CO_(3)+H_(2)O+CO_(2) to 2NaHCO_(3)`
Decimole =0.1 mole
1mole of `Na_(2)CO_(3)="1 mole of "CO_(2)`
Carbondioxide required for 0.1 mole of `Na_(2)CO_(3)=` 0.1 mole (or 4.4 grams)
Step 2: Regarding the requirement of calcium carbonate.
The balanced equaiton for the decomposition of calcium carbonate is
`CaCO_(3) to CaO+CO_(2)`
1 mole of `CO_(2)="1 mole of "CaCO_(3)`
14 grams of `CO_(2_)="100 grams of CaCO_(3)`
The weight of calcium carbonate to produce the required 4.4 grams carbondioxide `=(100)/(44) xx4.4 =10"gramas"`