100 mL of phosphorus pentachloride is totally decomposed to its trichloride at 1 atm and `546^(@)C`. How many molecules of chlorine are formed?

Explanation

Decomposition of phosphorus pentachloride is given as
`PCl_(5) to PCl_(3)+Cl_(2)`
1 mole of `PCl_(5)="1 mole of "Cl_(2)`
1 vol of `PCl_(5)="1 vol of "Cl_(2)`
100mL of `PCl_(5)="100mL of "Cl_(2)`
Give conditions`" STP conditions"`
`P_(1)=1 atm" "P_(2)=1atm`
`T_(1)=819K" "T_(2)=273K`
`V_(1)=100mL" "V_(2)=?`
The volume of `Cl_(2)` measured at STP
`V_(2)=(P_(1)V_(1))/(T_(1)) xx T_(2)/P_(2) =(1 xx 100 xx 273)/(819 xx 1) =33.33mL`
22400mL of `Cl_(2)` at STP =`6.022 xx 10^(23)"molecules"`
33.33mL of `Cl_(2)` at STP= ?
Number of molecules of chlorine obtained `=(33.33)/(22400) xx 6.022 xx 10^(23) =8.96 xx 10^(20)`