100 mL of each acetylene and oxygen are mixed. The mixture is strongly heated to complete the reaction and colled back to room temperature. What is the maximum volume of carbondioxide obtained. Why?

Explanation

The stoichiometric equation for burning of acetylene is given as
`2C_(2)H_(2)+5O_(2) to 4CO_(2)+2H_(2)O`
2 moles of `C_(2)H_(2)="5 moles of "O_(2)`
2 volume of `C_(2)H_(5)="5 volumes of "O_(2)`
100mL of `C_(2)H_(2)="250mL of "O_(2)`
40mL of `C_(2)H_(2)=100mL of O_(2)`
Hence the limiting reagent is oxygen
5 moles of `O_(2)="4 moles of "CO_(2)`
5 volumes of `O_(2)="4 volumes of "CO_(2)`
100mL of `O_(2)=?`
The maximum volume of `CO_(2)` formed `100 xx 4/5=80mL`
This is because no sufficient `O_(2)` is available.