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four grams of hydrocarbon (C(x)H(y)) on ...

four grams of hydrocarbon `(C_(x)H_(y))` on complete combustion gave 12grams of `CO_(2)`. What is the empirical formula of the hydrocarbon ? `(C=12 , H=1)`

A

`CH_(3)`

B

`C_(4)H_(9)`

C

CH

D

`C_(3)H_(8)`

Text Solution

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The correct Answer is:
D
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