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DeltaH^(0) for a reaction F(2) + 2HCl ra...

`DeltaH^(0)` for a reaction `F_(2) + 2HCl rarr 2HF + Cl_(2)` is given as `-352.8 kJ. Delta H_(f)^(0)` for HF is `-268.3 KJ mol^(-1)`, then `Delta H_(f)^(0)` of HCl would be

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`DeltaH = H_P -H_R = 2H_(HF) - 2H_(HCl)`
`= -352.8 KJ = 2(-268.3) - 2(H_(HCl))`
`2(H_(HCl)) = -536.6 + 352.8 = -183.8 kJ`.
(or) `H_(HCl) = -91.9 kJ mol^(-1)`.
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