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Latent heat of fusion of ice is 6 kJ mol...

Latent heat of fusion of ice is `6 kJ mol^(-1)`. Calculate the entropy change in the fusion of ice. 

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Change in entropy, `DeltaS = q_(rev)//T`
`q_(rev)`  = Latent heat of fusion = `6 kJ mol^(-1)`
`= 6000 J mol^(-1)`
  T = Freezing point of water = 273K.
`DeltaS = 6000/(273 = 21.98 JK^(-1) mol^(-1)) (or)`
`DeltaS = (6000)/(273 xx 18) = 1.22 JK^(-1)g^(-1)`.
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