The equilibrium constant of a reaction is 73. Calculate standard free energy change.

Explanation

Equilibrium constant K is related to `DeltaG^@` as,
`DeltaG^@ = -2.303 R T log K`. Substituting the values,
`K = 73 , T = 298 K and R = 8.314 J K^(-1).mol^(-1)`
`DeltaG^@ = -2.303 xx 8.314 xx 298 xx log_(10)`
`= -10.632 J mol^(-1)`
Standard free energy change = `-10.632 kJ mol^(-1)` .