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Zn((s))+Fe(aq)^(2+) Leftrightarrow Zn(aq...

`Zn_((s))+Fe_(aq)^(2+) Leftrightarrow Zn_(aq)^(2+) +Fe_((s)`. The vale of `K_(c)`for this reaction is `10^(23). Calculate the standard free energy change.

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Change in standard free energy,
`DeltaG^@ = -2.303 RT log_(10) K_c`
`DeltaG^@ = -2.303 xx 1.987 xx 298 xx log 10^(23)`
`= -13,570 cal mol^(-1)`
Standard free energy change for the reaction is `- 13.57 kcal mol^(-1)`.
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