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If S + O(2) rarr SO(2), DeltaH= -398.2kJ...

If `S + O_(2) rarr SO_(2), DeltaH= -398.2kJ`
`SO_(2) + (1)/(2) O_(2) rarr SO_(3), DeltaH= -98.7kJ , SO_(3) + H_(2)O rarr H_(2)SO_(4), DeltaH= -130.2 kJ`
`H_(2) + (1)/(2) O_(2) rarr H_(2)O, DeltaH= -227.3kJ`
The enthalpy of formation of sulphuric acid at 298K will be

A

`-854.4 K.J `

B

`-754.4 KJ `

C

`-650.3 KJ `

D

`433.7 KJ`

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The correct Answer is:
A
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AAKASH SERIES-CHEMICAL THERMODYNAMICS-OBJECTIVE EXERCISE - 2 (HESS LAW)
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