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1)C("Graphite") + O(2(g)) rarr CO(2(g)) ...

1)`C_("Graphite") + O_(2(g)) rarr CO_(2(g)) , DeltaH = -94 K.Cals`
2) `C_("Diamond") + O_(2(g)) rarr CO_(2(g)) , DeltaH =-94.5 K.Cals`
  From the above data the heat of transition of `C_("diamond") rarr C_("Graphite")`

A

`-50 Cal`

B

`-100 Cal `

C

`-500 Cal`

D

`100 Cal`

Text Solution

Verified by Experts

The correct Answer is:
C
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