Home
Class 11
CHEMISTRY
The ratio of the wave lengths of the fir...

The ratio of the wave lengths of the first line in the Lyman series of the spectrum of Hydrogen atom and the first line in the Balmer series of the spectrum of `He^(+)` is

A

`20//27`

B

`27//20`

C

`27//5`

D

`5//27`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    AAKASH SERIES|Exercise Level - I (EAMCET) (Exercise - VI (Miscellaneous))|24 Videos

  • ATOMIC STRUCTURE

    AAKASH SERIES|Exercise Level - I (MAIN) (Exercise -I (Fundamental particle , Atomic number and mass number , Atomic models, Nature of light , Spectra))|20 Videos

  • ATOMIC STRUCTURE

    AAKASH SERIES|Exercise Level - I (EAMCET) (Exercise -IV (Quantum numbers))|21 Videos

  • AROMATIC HYDROCARBONS

    AAKASH SERIES|Exercise OBJECTIVE EXERCIES - 3 (RECENT AIPMT/NEET QUESTIONS)|10 Videos

  • CHEMICAL BONDING

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE -3 (RECENT AIPMT/NEET QUESTIONS )|39 Videos

Similar Questions

Explore conceptually related problems

The ratio of the wave lengths of the first line in the Lyman series of the spectrum of Hydorgen atom and the first line in the Balmer series of the spectrum of He^(+) is

Calculate the wave number of the first spectral line in the Lyman series of He^(+) spectrum

Calculate the wave number of the first spectral line in the lyman series of He^(+) spectrum.

The ratio of longest wavelength line in the Balmer andaschen series of hydrogen spectrum is

Whenever a hydrogen atom emits a photon in the Balmer series

The first line is the Lyman series has wavelength lambda .The first line in Balmer series has wavelength

The ratio of the wavelength of the last line of Balmer series and the last line of Lyman series is :

What is the wave length of H, line in Balmer series of hydrogen spectrum? (R = Rydberg constant)

AAKASH SERIES-ATOMIC STRUCTURE-Level - I (EAMCET) (Exercise - V (Electronic configuration , Aufbau principle, Pauli.s Exclusion principle and Hund.s rule ))
  1. The atomic number of an element 'M' is 26. How many electrons are pres...

    Text Solution

    |

  2. Consider the ground state of Cr atom (Z = 24). The numbers of electron...

    Text Solution

    |

  3. Which is the first element to have 4d-electron in its electronic confi...

    Text Solution

    |

  4. In the ground state, an element has 13 electrons in its "M - shell". T...

    Text Solution

    |

  5. (A) : The electronic configuration of Cr is [Ar]3d^(5) 4s^(1) but not ...

    Text Solution

    |

  6. The electrons identified by quantum numbers n and l are I) n = 4, l...

    Text Solution

    |

  7. (A) : Fe^(3+) (g) is more stable than Fe^(2+) (g) (R) : Fe^(3+) (g) ...

    Text Solution

    |

  8. In which of the following Aufbau principle is violated?

    Text Solution

    |

  9. Which of the following electronic configuration is not possible?

    Text Solution

    |

  10. The configuration 1s^(2)2s^(2)2p^(5)3s^(1) shows

    Text Solution

    |

  11. Which of the following has maximum unpaird d-electrons ?

    Text Solution

    |

  12. Consider the ground state of Cr atom (Z = 24). The numbers of electron...

    Text Solution

    |

  13. Mass number of Li, Be and B are 7,9 and 10 respectively. Which of the ...

    Text Solution

    |

  14. The energy required to melt 1g. Ice is 33J. The number of quanta of ra...

    Text Solution

    |

  15. (A) : A spectral line will be seen for 2p(x) to 2p(y) transition. (R...

    Text Solution

    |

  16. When a greater number of electrons from excited hydrogen atoms reach t...

    Text Solution

    |

  17. What electronic transition in Li^(+2) produces the radiation of the sa...

    Text Solution

    |

  18. The wavelength of the spectral line, for the transition n = 2 to n=1 i...

    Text Solution

    |

  19. The ratio of the wave lengths of the first line in the Lyman series of...

    Text Solution

    |

  20. In Bohr series of lines of hydrogen spectrum, the third line from the ...

    Text Solution

    |