" The line "x-1=0" is the directrix of the parabola,"y^(2)-kx+8=0" .Then,one of the values of "k" is "

If the line x-1=0 is the directrix of the parabola y^2-k x+8=0 , then one of the values of k is (a) 1/8 (b) 8 (c) 4 (d) 1/4

If the line x-1=0 is the directrix of the parabola y^2-k x+8=0 , then one of the values of k is 1/8 (b) 8 (c) 4 (d) 1/4

If the line x-1=0 is the directrix of the parabola y^2-k x+8=0 , then one of the values of k is (a)1/8 (b) 8 (c) 4 (d) 1/4

If the line x-1=0 is the directrix of the parabola y^2-k x+8=0 , then one of the values of k is (a) 1/8 (b) 8 (c) 4 (d) 1/4

If the line x-1=0 is the directrix of the parabola y^2-k x+8=0 , then one of the values of k is 1/8 (b) 8 (c) 4 (d) 1/4

The directrix of the parabola x^(2)-4x-8y+12=0

The line x-1=0 is the directrix of a parabola, y^2=kx then Find the value of k.

x - 1 = 0 is the equation of directrix of the parabola y^(2) - kx + 8 = 0 . Then the value of k is _