10 gram of a solute was dissolved in 80 g of acetone at 30ºC to form an ideal solution. The vapour pressure was found to be 271 mm of Hg. Vapour pressure of pure acetone at `30^(@)` C is 283 mm Hg. The molecular weight of the solute is

1.0 gram of a non-volatile solute was dissolved in 100 gram of acetone (molecular mass = 58) at 298 K. The vapour pressure of solution was found to be 192.5 mm of Hg. Calculate the molecular mass of solute. The vapour pressure of pure acetone at 298 K is 195 mm of Hg.

A solutions is prepared by dissolving 394 g of a nonvolatile solute in 622 g of water. The vapour pressure of solution is found to be 30.74 mm Hg at 30^@C . If vapour pressure of water at 30^@C is 31.8mm Hg, what is the molar mass of solute?

In an experiment ,1 g of a non-volatile solute was disslved in 100 g of acetone ( molarcular mass = 58 ) at 298 K . The vapour pressure of the solution was found to be 192.5 mm Hg .The molecular weight of the solute is _________ g mol ^(-1) ( vapour pressure of acetone = 195 mm Hg )