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The rate constant of a reaction is 2.5xx...

The rate constant of a reaction is `2.5xx10^(-2)" L mol"^(-1)s^(-1)`. Calculate the initial rate with concentration `0.2" mol L"^(-1)`.

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From the units of rate constant,
Order of the reaction is `2`.
For a second order reaction, rate `=k["concentration"]^(2)`
Initial rate of the reaction `=2.5xx10^(-2)(0.2)^(2)`
`=1xx10^(-3)"mol"L^(-1)s^(-1)`
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