The initial concentration of ethyl acetane is `0.85 mol L^(-1)` . Following the acid catalysed hydrolysis the , concentrations of ester after 30 min and 60 min of the reaction are respectively ` 0.8 and 0.754 mol L^(-1)` . Calculate the rate constant and pseudo rate constant.

Explanation

Acid catalysed ester follows pseudo first order kinetics. The rate constant k is given as
`k=(2.303)/(t)log.(a)/(a-x)`
`k=(2.303)/(30)log.(0.85)/(0.05)=2.020xx10^(-3)"min"^(-1)("or")`
`k=(2.303)/(30)log.(0,80)/(0.046)=1.997xx10^(-3)"min"^(-1)`
The rate constant (k) is the product of pseudo first order rate constant (k.).
Concentration of water, taken as constant as `55.5` "mol"L^(-1)`
`k=k.[H_(2)O]`
Substituting the values, `1.997xx10^(-3)=k.[55.5]`
Pseudo rate constant=k.
`3.6xx10^(-5)L "mol"^(-1)"min"^(-1)`