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Why is the reduction of a metal oxide if...

Why is the reduction of a metal oxide if the metal formed is in liquid state at the temperature of reduction?

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The entropy is higher if the metal is in liquid state than when it is in solid state. The values of `Delta S` of the reduction process becomes more positive, as a result the `Delta G` becomes more negative when metal formed is in the molten state than in solid state. Thus reduction becomes easier.
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