An ion with mass number 37 possesses one unit of negative charge. If  the ion contains `11.1%` more neutrons than the electrons, write its symbol. 

Explanation

As the ion carries one unit of negative charge, it will have one electron more than the number of protons. Let the number of electrons = x. Number of protons `=x-1`
Number of neutrons `=x+(x xx11.1)/(100),37=x-1+1.111x=2.111x-1,x=(38)/(2.111)=18`
Number of electrons `= 18`. Number of protons `= 18 - 1 = 17`. Number of neutrons `= 37-17 = 20` Number of neutronsThe ion under discussion is chloride and its symbol is `Cl^(-)`