Find the momentum of a particle whose de Broglie wavelengh is `1Å`.

Explanation

de Broglie wave length, `lambda=1Å=1.0xx10^(-1)m`
`lambda=(h)/(p)" or momentum "p=(h)/(lambda)=(6.6256xx10^(-34)kgm^(2)s^(-1))/(1.0xx10^(-10)m)=6.6256xx10^(-24)kg ms^(-1)`