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100 ml of a sample of water requires 1.9...

100 ml of a sample of water requires 1.96 mg of potassium dichromate in the presence of 50% `H_2SO_4` for the oxidation of dissolved organic matter in it. Calculate the chemical oxygen demand.

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One gram equivalent of any oxidant can give, one equivalent weight of oxygen (8g) `1.96XX10^(-3)gK_(2)Cr_(2)O_(7)rarr(8.1xx1.96xx10^(-3))/(49)=0.32g`
Chemical oxygen demand of the given 100 ml sample of water = 3.2 ppm
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