Bond angle in `"PH"_(4)^(" "+)` is higher than that in `"PH"_(3)`. Why ?

Explanation

In `PH_(4)^(+)`, phosphorous undergo `SP^(3)` hybridization, but in `PH_(3)` phasphorous uses pure p-oribitals for bonding. Hence bond angle in `PH_(3)` is nearly `90^(@)`.