Home
Class 12
CHEMISTRY
CH3 -CH2 - CH2- Br overset(Alc.KOH)to C...

`CH_3 -CH_2 - CH_2- Br overset(Alc.KOH)to CH_3 -CH =Br overset(HBr)to CH_3 - overset(Br) overset(|)(CH) -CH_3`

A

X = dilute NaOH, `20^@C` , Y = HBr/acetic acid, `20^@C`

B

X = Concentrated alcoholic NaOH, `80^@C` , Y = HBr/acetic acid, `20^@C`

C

X = dilute NaOH, `20^@C` , Y` = HBr//CH_3 , 0^@C`

D

X = Concentrated alcoholic NaOH, `80^@C , Y = HBr//CHCl_3,0^@C`

Text Solution

Verified by Experts

The correct Answer is:
B
`CH_3 - CH_2 - oversetunderset(|)(Br)(C )H_2 underset(-KBr)overset(alc KOH)(to) H_3C - CH = CH_2 overset(HBr)(to) H_3C - oversetunderset(|)(Br)(C )H - CH`
Promotional Banner

Similar Questions

Explore conceptually related problems

CH_3 - overset(Cl)overset(|) CH -CH_3 overset(Alc.KOH)to CH_3 -CH =CH_2 underset(2 . H_2 O_2 // OH^(-))overset(1. BH_3)to CH_3 - CH_2 - overset(OH) overset(|)CH_2

CH_3 CH_2 CH_2 OH overset( x) to CH_3 CH= CH_2 , The reagent 'X' is

CH_3 - overset(Br) overset(|) CH - overset C H_3 overset (Alc.KOH ) to CH_3 -CH =CH_2 underset("peroxide") overset(HBr)to CH_3 -CH_2 -CH_2 -Br

CH_3 - CH_2 - CH_2 - CH_3 underset(Delta)overset(AlCl_3)to CH_3 - underset(CH_3)underset(|)CH-CH_3 Above reaction is an example of :

CH_3- overset(CH_3) overset(|) C=CH_2 overset(HCI) to CH_3 - underset(Cl) underset(|) overset(CH_3) overset(|) C-CH_3

CH_3 - CH_2 - overset(O ) overset(|| ) C - underset(CH_3) underset(|) overset(CH_3) overset(|) C- CH_3 overset(PhCO_2 H)to A , A will be

IUPAC name for the following compound is CH_3 -overset(overset(CI)|) (CH)- CH_2 -overset(overset(CH_2 - CH_3)|) (CH -CHO) underset(5)(CH_3) -underset(4)overset(overset(CI)|) CH -underset(3) CH_2 -underset(2)overset(overset(CH_2 - CH_3)|) (CH )-underset(1) CHO

Name the following compounds according to IUPAC system. (i) CH_(3) - CH_(2) - underset (CH_(2)Cl) underset(|)(CH) - overset (CH_(2)OH) overset(|) (CH) - underset (CH_(3)) underset (|) (CH) - CH_(3) CH_(3)- underset (CH_(3)) underset(|) (CH) -CH_(2) - underset(OH) underset(|) (CH) - overset (CH_(2)OH) overset(|) (CH) - CH_(2) (iii) (iv) H_(2)C = CH - underset (OH)underset (|) (CH) - CH_(2) - CH_(2) - CH_(3) (v) CH_(3) - underset (CH_(3)) underset ( |) C = underset (Br)underset(|) C - CH_(2)OH

Consider the following organic compound, overset(1)CH_3 - overset(2)CH_2- overset(3)CH_2- overset(4)CH_2-Coverset(5)H_2-C overset(6)H_2 - C overset(7)H_3 To make it chiral compound, the attack should be on carbon