Home
Class 12
CHEMISTRY
2NaOH+SO(2) to A+H(2)O B+H(2)O+SO(2) t...

`2NaOH+SO_(2) to A+H_(2)O`
`B+H_(2)O+SO_(2) to 2NaHSO_(3). A` and B are

A

`A-Na_(2)SO_(3), B-Na_(2)SO_(3)`

B

`A-NaHSO_(3), B-Na_(2)SO_(3)`

C

`A-Na_(2)SO_(4), B-Na_(2)O`

D

`A-NaHSO_(3), B-Na_(2)SO_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A

`2NaOH+SO_(2) to Na_(2)SO_(3)+H_(2)O, NaOH+SO_(2) to NaHSO_(3)`.
Promotional Banner

Topper's Solved these Questions

  • VIA GROUP ELEMENTS

    AAKASH SERIES|Exercise PRACTICE SHEET - 3 (Linked Comprehension type questions)|6 Videos
  • VIA GROUP ELEMENTS

    AAKASH SERIES|Exercise PRACTICE SHEET - 3 (Match the following questions)|2 Videos
  • VIA GROUP ELEMENTS

    AAKASH SERIES|Exercise PRACTICE SHEET - 2 (Integer answer type Questions)|6 Videos
  • VA GROUP ELEMENTS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|51 Videos
  • VII GROUP ELEMENTS

    AAKASH SERIES|Exercise OBJECTIVE EXERCISE -4|55 Videos

Similar Questions

Explore conceptually related problems

Balance the following chemical equations. (AS1) (a) NaOH + H_(2)SO_(4) to Na_(2)SO_(4) + H_(2)O (b) Hg (NO_(3)) + KI to HgI_(2) + KNO_(3) (c) H_(2) + O_(2) to H_(2)O (d) KClO_(3) to KCl + O_(2) (e) C_(3)H_(8) + O_(2) to CO_(2) + H_(2)O

In aqueous solutions H_(2) SO _(4) ionises as: H _(2) SO_(4) + H _(2) O hArr H _(2) SO _(24 ) ^(-) + H _(3) O ^(+) , K a _(1) H_(2) SO _(4) ^(-) + H_(2) O hArr SO _(4) ^(2-) + H_(3) O ^(+) , Ka _(2). The relation between Ka _(1) and Ka _(2) is

Certain reactions regarding H_(2)SO_(4) are given H_(2)SO_(4)+NaOH to NaHSO_(4)+H_(2)O" "H_(2)SO_(4) +2NaOH to Na_(2)SO_(4) +2H_(2)O C_(12)H_(22)O_(11)+H_(2)SO_(4) to 12C+11H_(2)O These reactions shows that

Passage - VI : Industrially sulphuric acid is produced by the following steps: Stage I : S+O_(2) overset(Delta)to SO_(2) Stage II : 2SO_(2) +O_(2) overset(V_(2)O_(5))to 2SO_(3) Stage III : SO_(3)+H_(2)O to H_(2)SO_(4) Since the reaction between SO_(3) and H_(2)O is violent, SO_(3) is passed into 98% H_(2)SO_(4) to produce oleum (H_(2)S_(2)O_(7)) Pure H_(2)SO_(4) does not react with metal because -

Passage - VI : Industrially sulphuric acid is produced by the following steps: Stage I : S+O_(2) overset(Delta)to SO_(2) Stage II : 2SO_(2) +O_(2) overset(V_(2)O_(5))to 2SO_(3) Stage III : SO_(3)+H_(2)O to H_(2)SO_(4) Since the reaction between SO_(3) and H_(2)O is violent, SO_(3) is passed into 98% H_(2)SO_(4) to produce oleum (H_(2)S_(2)O_(7)) Ionically the reaction between H_(2)SO_(4) & Mg may be presented as, Mg+2H_(3)O^(+) to Mg^(2+)+H_(2) uarr +2H_(2)O Therefore, in the given reaction -

C_(2)H_(5)OH overset(K_(2)Cr_(2)O_(7)//H_(2)SO_(4))to A overset(K_(2)Cr_(2)O_(7)//H_(2)SO_(4))to B A and B in the above reaction are

Balance the following equations and write down the stoichiometric proportions. (a) C+O_(2) to CO_(2) (b) H_(2)+Cl_(2) to HCl (c ) N_(2)+H_(2) to NH_(3) (d) Fe+O_(2) to Fe_(2)O_(3) (e ) CaCO_(3)+HCl to CaCl_(2)+H_(2)O+CO_(2) (f) MnO_(2)+HCl to MnCl_(2)+H_(2)O+Cl_(2) (g) Mg(OH)_(2)+HCl to MgCl_(2)+H_(2)O (h) KI+H_(2)SO_(4) to KHSO_(4)+I_(2)+SO_(2)